postgresql json aggregate

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Answer by ceadreak for postgresql json aggregate

May 23, 2016, 2:09 pm

SELECT pid from activity a, ( select json_agg(project) from project where code = a.code ) as p Something like that ...

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Answer by Abelisto for postgresql json aggregate

May 23, 2016, 2:04 pm

select pid, json_agg(json_build_object('code',code,'name',name)) from ... group by pid

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May 23, 2016, 2:19 pm

I'm using postgres 9.4, I have the following query: SELECT pid, code, name FROM activity, ( SELECT code FROM project ) projects WHERE activity.pcode = projects.code; which return this following...

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